1.求把sql语句转成tinkPHP 的形式怎么写
2.java.lang.NullPointerException
3.eval(function(p,a,c,k,e,r) 解密

求把sql语句转成tinkPHP 的形式怎么写

       建议建立一个 modelView 

public $viewFields = array(

        'sr_jxc_inventory_log' => array('_as'=>'L''goods_id','warehouse_id','sum'=>array(

            'actual_number'=>'js'

            ),

            'sum' => array(

                 'case' => array(

                            'when' => 'actual_number> 0',

                            'then' => 'actual_number',

                            'else' => '0'

                         ),

                         '_as' => 'sr'

             ),

             'sum' => array(

                 'case' => array(

                     'when' => 'actual_number <0',

                     'then' => 'actual_number',

                     'else' => '0'

                 ),

                 '_as' => 'zc'

             ),

            ),'pid'),

        'sr_goods' => array('_as'=>'G','model','factory','barcode','_on' => 'style.id=color.pid'),

        'sr_jxc_ware' => array('_as'=>'W','name','_on' => 'style.id=color.pid'),

       );

       其实也自己瞎搞的，这样的农场系统源码下载还真没搞过，实在不行直接运行源码就好了，idea怎么查看app源码如果可以的拐点抄底指标公式源码话，请务必告知一声。腾讯工具箱源码

java.lang.NullPointerException

       å¾ˆå¤šå¯èƒ½ä¸ºnull的情况你都没处理，当然会出NullPointerException 错误

       æ¯”如：

       String username=request.getParameter("username");

       String password=request.getParameter("password");

       String str="select * from tb_user where"+"username="+username+"and password="+password;

       åº”该改成：

       String username=request.getParameter("username");

       String password=request.getParameter("password");

       if(username != null && password != null){

       String str="select * from tb_user where"+"username="+username+"and password="+password;

       â€¦â€¦â€¦â€¦â€¦â€¦

       â€¦â€¦â€¦â€¦â€¦â€¦

       }

       ä¸‹é¢çš„代码自己再检查检查，类似的情况都要先判断

eval(function(p,脚本答题源码怎么用a,c,k,e,r) 解密

       直接使用在线解密工具，已测试可以解密此文件

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